Asked by pau

how many liters of distilled water must be added to 80 liters of 60% acid solution to obtain a 50 % acid solution?
Answered by Reiny
amount added ..... x L
solve for x,

.6(80) + 0.0x = .5(80+x)
48 = 40 + .5x
x = 16
Answered by Reiny
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