Asked by Noor
Question: 1 The product of two positive numbers is 15876 and the large one is 9 times the other. Find the numbers.
Question:2
Th sum of the squares of two positive whole numbers is 794. If one of the numbers is 13 , find the other.
Question:2
Th sum of the squares of two positive whole numbers is 794. If one of the numbers is 13 , find the other.
Answers
Answered by
Damon
x y = 15876
y = 9 x
so
9 x^2 = 15876
x^2 = 1764
x = 42
===================
169 + x^2 = 794
x^2 = 625
x = 25
y = 9 x
so
9 x^2 = 15876
x^2 = 1764
x = 42
===================
169 + x^2 = 794
x^2 = 625
x = 25
Answered by
Bosnian
1 .
a = first number
b = second number
The large one is 9 times the other.
This mean :
b = 9 a
a * b = 15876
a * 9 a = 15876
9 a ^ 2 = 15876 Divide both sides by 9
a ^ 2 = 15876 / 9
a ^ 2 = 1764
a = sqroot ( 1764 )
a = 42
b = 9 a = 9 * 42 = 3789
2.
a = first number
b = second number ( In this case b = 13 )
The sum of the squares of two positive whole numbers is 794.
This mean :
a ^ 2 + b ^ 2 = 794
a ^ 2 + 13 ^ 2 = 794
a ^ 2 + 169 = 794 Subtract 169 to both sides,
a ^ 2 + 169 - 169 = 794 - 169
a ^ 2 = 625
a = sqroot ( 625 ) = 25
a = first number
b = second number
The large one is 9 times the other.
This mean :
b = 9 a
a * b = 15876
a * 9 a = 15876
9 a ^ 2 = 15876 Divide both sides by 9
a ^ 2 = 15876 / 9
a ^ 2 = 1764
a = sqroot ( 1764 )
a = 42
b = 9 a = 9 * 42 = 3789
2.
a = first number
b = second number ( In this case b = 13 )
The sum of the squares of two positive whole numbers is 794.
This mean :
a ^ 2 + b ^ 2 = 794
a ^ 2 + 13 ^ 2 = 794
a ^ 2 + 169 = 794 Subtract 169 to both sides,
a ^ 2 + 169 - 169 = 794 - 169
a ^ 2 = 625
a = sqroot ( 625 ) = 25
Answered by
imran said
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Answered by
Anonymous
Yi+5455=54
Answered by
Farhan
15
Answered by
M Asad
Very good explanation.
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