Asked by BARNABAS
The x and y components of a vector A are 4 and -5 respectively and Vector B are -2 and 1 respectively. If A-B+3C=0, find the Cartesian coordinates for vector C?
Answers
Answered by
bobpursley
(4-(-2)+3Cx)i + (-5-1+3Cy)j=0
check that, then solve for Cx
4+4=-3Cx or Cx=-8/3
-5-1=-3Cy
Cy=2
check all that, I did it in my head.
check that, then solve for Cx
4+4=-3Cx or Cx=-8/3
-5-1=-3Cy
Cy=2
check all that, I did it in my head.
Answered by
Mukupili
A=4x-5y
B=-2x+1y
--------
6x-6y
But A-B+3C=0
therefore, 3C= A-B
--- ---
3 3
C= A-B
---
3
But A-B = 6x -6y
therefore, A-B
the ---
3
6x-6y
-----
3
= 2x-2y
Therefore, C= 2×-2y
B=-2x+1y
--------
6x-6y
But A-B+3C=0
therefore, 3C= A-B
--- ---
3 3
C= A-B
---
3
But A-B = 6x -6y
therefore, A-B
the ---
3
6x-6y
-----
3
= 2x-2y
Therefore, C= 2×-2y
Answered by
Mukupili
A=4x-5y
B=-2x+1y
--------
6x-6y
But A-B+3C=0
therefore,
C= A-B
---
3
But A-B = 6x -6y
therefore,
6x-6y
-----
3
= 2x-2y
Therefore, C= 2×-2y
B=-2x+1y
--------
6x-6y
But A-B+3C=0
therefore,
C= A-B
---
3
But A-B = 6x -6y
therefore,
6x-6y
-----
3
= 2x-2y
Therefore, C= 2×-2y
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