Asked by Anonymous
Written in simplest form,
3x^3-27xy^2 / 12x^2+36xy is:
(1) x+3y/4
(2) x+4y/3
(3) x-3y/4
(4) x-3y/4(x+3y)
My work:
3x^327xy^2/12x^2+36xy=3x(x^2-9y^2/3x(4x+12y)=x^2-9y^2/4(x+3y)
3x^3-27xy^2 / 12x^2+36xy is:
(1) x+3y/4
(2) x+4y/3
(3) x-3y/4
(4) x-3y/4(x+3y)
My work:
3x^327xy^2/12x^2+36xy=3x(x^2-9y^2/3x(4x+12y)=x^2-9y^2/4(x+3y)
Answers
Answered by
Reiny
you did not finish at the end
3x(x^2-9y^2/(3x(4x+12y)) is correct, notice the brackets at the denominator
= 3x(x-3y)(x+3y)/((3x)(4)(x+3y))
= (x-3y)/4 , x ≠ 3y
looks like choice #1, if you had included the brackets
3x(x^2-9y^2/(3x(4x+12y)) is correct, notice the brackets at the denominator
= 3x(x-3y)(x+3y)/((3x)(4)(x+3y))
= (x-3y)/4 , x ≠ 3y
looks like choice #1, if you had included the brackets
Answered by
Steve
actually, that's x ≠ -3y, but it does not affect the final answer.
Just sayin' ...
Just sayin' ...
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