Asked by Anonymous
a rectangular piece of cardboard is twice as long as it is wide . from each of its for corners, a square piece 3 inches on a side cut out. the flaps at each corner are then turned up to form an open box. if the volume of the box is 168 cubic inches, what were the original dimensions of the piece of cardboard?
Answers
Answered by
Melodee
Length (L) = 2x
Width (W) = x
Height (H) =3
Volume (V) =168
Formula for the volume:
V=L x W x H
Hence,
(2x)(x)(3)=168
6x^2=168
x^2=168/6
x= 2 times the sqrt of 7
Answer:
W= 2 times the sqrt of 7 inches
L= 4 times the sqrt of 7 inches
Width (W) = x
Height (H) =3
Volume (V) =168
Formula for the volume:
V=L x W x H
Hence,
(2x)(x)(3)=168
6x^2=168
x^2=168/6
x= 2 times the sqrt of 7
Answer:
W= 2 times the sqrt of 7 inches
L= 4 times the sqrt of 7 inches
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