Asked by Anonymous
The sum of the length, width, and height of a box is 80 cm. The length is 10 cm less than twice the sum of the width and the height, and twice the width exceeds the height by 6 cm. Find the height of the box.
Answers
Answered by
Steve
If the dimensions are x,y,z then we have
x+y+z = 80
x = 2(y+z)-10
2y = z+6
Now just solve for z.
x+y+z = 80
x = 2(y+z)-10
2y = z+6
Now just solve for z.
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