Asked by FLOR
HENRY, ANDY AND JOE SHARED SOME SWEETS IN THE RATIO 15:12:9 RESPECTIVELY. HENRY HAD 6 MORE SWEETS THAN ANDY. IF ANDY GAVE 9 SWEETS TO JOE, HOW MANY SWEETS WOULD JOE HAVE?
Answers
Answered by
Steve
(a+6)/a = 15/12
12(a+6) = 15a
12a+72 = 15a
3a = 72
a = 24
a/j = 12/9, so
24/j = 12/9
j = 18
So, if Andy gave Joe 9, he'd have 27
12(a+6) = 15a
12a+72 = 15a
3a = 72
a = 24
a/j = 12/9, so
24/j = 12/9
j = 18
So, if Andy gave Joe 9, he'd have 27
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