Question

HENRY, ANDY AND JOE SHARED SOME SWEETS IN THE RATIO 15:12:9 RESPECTIVELY. HENRY HAD 6 MORE SWEETS THAN ANDY. IF ANDY GAVE 9 SWEETS TO JOE, HOW MANY SWEETS WOULD JOE HAVE?

Answer 1

(a+6)/a = 15/12
12(a+6) = 15a
12a+72 = 15a
3a = 72
a = 24

a/j = 12/9, so
24/j = 12/9
j = 18

So, if Andy gave Joe 9, he'd have 27