Question

You throw a glob of putty straight up toward the ceiling. Which is 3.60 m above the point where the putty leaves your hand. The initial speed of the putty leaves  as it leaves your hand is 9.50m/s.<br>
(A) what is the speed of the putty just before it strikes the ceiling?<br>
(B) how much time from when it leaves your hand does it take the putty to reach the ceiling?

Answer 1

A. V^2 = Vo^2 + 2g*h = 9.5^2 - 19.6*3.6 = 19.69.
V = 4.44 m/s.

B. V = Vo + g*t = 4.44.
9.5 - 9.8t = 4.44.
-9.8t = -5.06.
t = 0.533 s.