Asked by Mr. Alexander
Suppose $A$ and $B$ are digits for which the product of the two-digit numbers $\underline{2A}$ and $\underline{AB}$ is 1971. Find the sum of $A$ and $B$.
Note: This is LaTeX, so if you need to render it, then go ahead
Note: This is LaTeX, so if you need to render it, then go ahead
Answers
Answered by
Steve
why bother wit LaTex? Just type it in:
Suppose A and B are digits for which the product of the two-digit numbers 2A and AB is 1971. Find A+B.
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
Suppose A and B are digits for which the product of the two-digit numbers 2A and AB is 1971. Find A+B.
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
Answered by
nushi
Suppose A and B are digits for which the product of the two-digit numbers 2A and AB is 1971. Find A+B.
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
Answer
Suppose A and B are digits for which the product of the two-digit numbers 2A and AB is 1971. Find A+B.
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
2A*AB = (20+A)(10A+B) = 1971
1971 = 3^3*73
So, its only two-digit factors are
27 and 73
A+B=10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.