Midville.........................Carmine
distance = X
truck..............|...............Car
truck moves 40 mph*1.25 hrs = 50 miles
The car moves from carmine to 110 miles out(55 mph x 2 hrs = 110 miles)
Therefore, the truck moves from 50 miles out of Midville while the car moves from Carmine to the 110 mile spot. The truck moved 60 miles in that time frame.
Distance = rate x time
truck moved 60 miles @ 40 mph or 1.5 hours. The car moved X-110 in that same time of 1.5 hrs so
(X-110)/55 = 1.5 hrs.
Solve for X.
Check me out on that. It looks ok to me. Hopefully one of the math guys will check this.
A truck left midville at 2:00 p.m. for Carmine, traveling at 40 mil/hr. At 3:15 p.m. a car left Carmine for Midville at 55 mi/hr. The truck and car passed each other exactly 2 hours before the car reached Midville. How far is it from Midville to Carmine?
Can someone please help me?
Thank you.
5 answers
clearly the vehicles met 110 miles from Midville.
At 40mi/hr, it took the truck 1:22.5 to cover that distance. So, the vehicles met at 2:00 + 1:22.5 = 3:22.5
The car had only been going for 7.5 minutes, covering only 6.875 miles.
So, the towns are 116.875 miles apart.
At 40mi/hr, it took the truck 1:22.5 to cover that distance. So, the vehicles met at 2:00 + 1:22.5 = 3:22.5
The car had only been going for 7.5 minutes, covering only 6.875 miles.
So, the towns are 116.875 miles apart.
At 40 mph doesn't it take the truck 110/40 = 2.75 hours to cover that distance?
hmmm. yeah. I wonder how I
(a) got that answer, and
(b) didn't immediately notice that it made no sense.
Anyway, Rachel, you can see how to fix it and get the right answer. Unlike me, check it for consistency!
(a) got that answer, and
(b) didn't immediately notice that it made no sense.
Anyway, Rachel, you can see how to fix it and get the right answer. Unlike me, check it for consistency!
This is really old but it seems this is not cleared so.....
To find the distance from Midville to where the car and truck met. We can use the cars speed and knowing that it took 2 hours to get cover that distance.
D = R x T, and the time was 2 hours going at 55 mph so we get 110 miles.
Now lets represent that in terms of the truck. Thee truck left 1 and 1/4 hour earlier than the other car and got to the meetup spot. We can represent the unknown time as 't'. D = R x T, so 110 = 40 x (t + 5/4).
Divide both sides by 40 and you get (t+5/4) = 11/4. Sub 5/4 from both sides and you get t = 6/4 = 3/2. 3/2 is the time to travel the other distance from Carmine to the meeting spot. If we add that to the distance from Midville to the meeting spot we have 110 + 3/2 * 55 = 192.5.
The distance from Midville to Carmine is 192.5 miles.
To find the distance from Midville to where the car and truck met. We can use the cars speed and knowing that it took 2 hours to get cover that distance.
D = R x T, and the time was 2 hours going at 55 mph so we get 110 miles.
Now lets represent that in terms of the truck. Thee truck left 1 and 1/4 hour earlier than the other car and got to the meetup spot. We can represent the unknown time as 't'. D = R x T, so 110 = 40 x (t + 5/4).
Divide both sides by 40 and you get (t+5/4) = 11/4. Sub 5/4 from both sides and you get t = 6/4 = 3/2. 3/2 is the time to travel the other distance from Carmine to the meeting spot. If we add that to the distance from Midville to the meeting spot we have 110 + 3/2 * 55 = 192.5.
The distance from Midville to Carmine is 192.5 miles.
2 answers