Asked by Anonymous
Find x
√2x/9.81= √(300+h)^2+60^2/150
Thankyou!
√2x/9.81= √(300+h)^2+60^2/150
Thankyou!
Answers
Answered by
Anonymous
Sorry it was:
√2x/9.81= √(300+x)^2+60^2/150
√2x/9.81= √(300+x)^2+60^2/150
Answered by
Steve
I'll go out on a limb here and assume you meant
(√2x)/9.81= √((300+x)^2+60^2)/150
square both sides and you have (roughly)
4x/96 = (x^2+600x+93600)/22500
2x^2-675x+187200 = 0
that has no real roots.
So, if I got it wrong, fix it and solve using the same method. Here's how wolframalpha worked it.
http://www.wolframalpha.com/input/?i=%28%E2%88%9A2x%29%2F9.81%3D+%E2%88%9A%28%28300%2Bx%29^2%2B60^2%29%2F150
If I got the syntax wrong, adjust the input and see the new solution.
(√2x)/9.81= √((300+x)^2+60^2)/150
square both sides and you have (roughly)
4x/96 = (x^2+600x+93600)/22500
2x^2-675x+187200 = 0
that has no real roots.
So, if I got it wrong, fix it and solve using the same method. Here's how wolframalpha worked it.
http://www.wolframalpha.com/input/?i=%28%E2%88%9A2x%29%2F9.81%3D+%E2%88%9A%28%28300%2Bx%29^2%2B60^2%29%2F150
If I got the syntax wrong, adjust the input and see the new solution.
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