Asked by Steve

What is the area of rectangle wxyz with vertices w(0,1),x(3,4),y(-1,8) z (-4,5) to the nearest unit?

Answers

Answered by Steve
if you trust that the vertices do in fact form a rectangle, then just find the lengths of sides wx and wz

wx has length 3√2
wz has length 4√2

the rectangle thus has area 24
Answered by Steve
thank you
Answered by netts
Hello Steve!

To help everyone else who come across this problem and still don't get it like me,

to find the "lengths" you will have to use the Distance Formula.

d = ã(x2 - x1)^2 +(y2 - y1)^2)

so, just insert the wx values in this and then do it again for the wz values and times the two values together to get your answer. Hoped I helped!! :)
Answered by netts
*d = ã(x2 - x1)^2 +(y2 - y1)^2)
Answered by netts
*the symbol won't show for me, sorry!**
d = (square root)((x2 - x1)^2 +(y2 - y1)^2)
Answered by R8F
24 square units
Answered by k
24
Answered by Bakugo
dose anyone got all the answers im so behind
Answered by Yet another weeb
1 is b.22 in.
2 is b. 20 ft.
3 is d. 24 square units

That's all I have so far
Answered by depression
i got 10 for number 2 weeb
Answered by Anonymous
J
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