Asked by edward
                the graph of the relation y=x^2+2x+k, passes through 2 and 0 find the value of k. plz explain 
            
            
        Answers
                    Answered by
            Steve
            
    It appears that you mean it passes through the point (2,0). So, plug those values in and you have
4+4+k = 0
k = -8
so, y = x^2+2x-8
    
4+4+k = 0
k = -8
so, y = x^2+2x-8
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