Asked by edward
the graph of the relation y=x^2+2x+k, passes through 2 and 0 find the value of k. plz explain
Answers
Answered by
Steve
It appears that you mean it passes through the point (2,0). So, plug those values in and you have
4+4+k = 0
k = -8
so, y = x^2+2x-8
4+4+k = 0
k = -8
so, y = x^2+2x-8
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