Asked by Stephen


t^2/ã(t^2+1) - ã(t^2+1)
-------------------------
t^2

Is the final answer -1/t^2 sqrt(t^2+1)
Answered by Stephen
The a is supposed to be a square root
Answered by Steve
you have

t^2/√(t^2+1) - √(t^2+1)
----------------------------
t^2

Combine the terms in the numerator and denominator

t^2 - (t^2+1)
---------------------
t^2 √(t^2+1)

-1/(t^2 √(t^2+1))
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