Area = length times width
800 = L * 2L
800 = 2L*2
400 = L^2
20 = L
800 = L * 2L
800 = 2L*2
400 = L^2
20 = L
According to the given information, the width of her yard is twice as long as the length. So, the width would be 2x.
The formula for the area of a rectangle is length multiplied by width. Given that the area is 800 sq.ft, we can set up the equation:
Area = Length × Width
800 = x × 2x
Simplifying the equation, we get:
800 = 2x^2
To find the value of x, we need to solve this quadratic equation. Let's divide the equation by 2:
400 = x^2
Taking the square root of both sides of the equation:
√400 = √(x^2)
20 = x
Therefore, the length of Raquel's yard is 20 ft.
Now, to find the width, we multiply the length by 2:
Width = 2 × Length
Width = 2 × 20
Width = 40 ft
So, the width of Raquel's yard is 40 ft and the length is 20 ft.
Let's assume the length of her yard is represented by 'L' and the width of her yard is represented by 'W'.
From the given information, we know that the area of her lawn is 800 sq.ft. We can write the equation:
L * W = 800
It is also given that the width of her yard is twice as long as the length of the yard. We can write the equation:
W = 2L
Now we can solve this system of equations to find the values of L and W.
Substitute the value of W from the second equation into the first equation:
L * (2L) = 800
Simplify:
2L^2 = 800
Divide both sides of the equation by 2:
L^2 = 400
Take the square root of both sides to find L:
L = √400 = 20 ft
Since the width, W, is twice the length:
W = 2L = 2 * 20 = 40 ft
Therefore, the width of Raquel's yard is 40 feet, and the length of her yard is 20 feet.