Two equations to be solved simultaneously.
Let X = g C3H8
and Y = g C2H2
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X + Y = 2.5 (equation 1)
mols CO2 from C3H8 + mols CO2 from C2H2 = 1.5*(mols H2O from C3H8 + mols H2O from C2H2). Turning that into a second equation
(4X/44) + (3X/44) = 1.5[(Y/26) + (2Y/26)] (equation 2)
Solve for Y.
Post your work if you get stuck.
A mixture of C3H8 and C2H2 has a mass of 2.5 g . It is burned in excess O2 to form a mixture of water and carbon dioxide that contains 1.5 times as many moles of CO2 as of water. Find the mass of C2H2 in the original mixture.
1 answer
1 answer