Asked by mrajput
Rodney and Cauls’s houses having distance of eleven km Rodney start from his house by walking at the speed of 6 km / hr , Caouls at 5 km / hr at what distane they will meet , if Rodney start his journey later by 5 minutes then which time they will meet ?
Answers
Answered by
Henry
A. d = 6t + 5t = 11 km.
11t = 11.
t = 1 hr. = Time they meet.
d1 = 6km/h * 1h = 6km. = Distance Rodney
traveled when they met.
d2 = 5km/h * 1h = 5km = Distance Ca0uls
traveled.
B. 6(t-1/12) + 5t = 11 km.
6t-0.5 + 5t = 11.
11t = 11.5.
t = 1.045 h.
11t = 11.
t = 1 hr. = Time they meet.
d1 = 6km/h * 1h = 6km. = Distance Rodney
traveled when they met.
d2 = 5km/h * 1h = 5km = Distance Ca0uls
traveled.
B. 6(t-1/12) + 5t = 11 km.
6t-0.5 + 5t = 11.
11t = 11.5.
t = 1.045 h.
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