Question

The following formula relates the distance S (in feet) traveled by a vehicle during an emergency stop to the time T (in seconds) it takes to arrive at a complete stop: s(t)=16t^{2}

At the scene of an accident, Bill uses skid marks to determine the braking distance of one of the vehicles involved was about 650 feet.

What is the corresponding braking time in seconds?
Algebra
650ft/117.3ft/s=5.5 Is NOT the answer. Nor is 40.6 nor 7.4 nor 8.8 nor 16.2 nor 6.5. Nor is 0! Thinking they didn't stop at all before the crash!

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