Question

length of the rectangle is five more than twice its width .area of the rectangle is 52 sq meter. find the length of the rectangle

have my own sol. pls. continue
L=5+2w
LW=52
(5+2w)w=52
2w^2+5w=52
2w^2+5w-52=0
soo. pls could someone continue this~?

Answer 1

your equation factors to
(w-4)(2w + 13) = 0

so w = 4 or w = -13/2, which makes no sense

so the width is 4 and the length is 2(4) + 5 or 13

Answer 2

2w^2+5w-52=0.00

Answer 3

2w^2+5w-52=0