i = .075/4 = .01875
1. n = 4(3) = 12
amount = 3000(1.01875)^12 = 3749.15
2.
3000(1.01875)^n = 6000 , where n is the number of quarter years
1.01875^n = 2
take logs of both sides and use use of logs
n log 1.01875 = log 2
n = log 2/log 1.01875 = appr 37.313
= 37.313../4 or appr 9.3 years
Can anybody show me step by step pls?
A man invests $3000 in an account that pays 7.5% interest per year, compounded quarterly.
1. Find the amount after 3 years? (Round your answer to the nearest cent.)
how much $?
2. How long will it take for the investment to double? (Round your answer to two decimal places.)
how many yrs?
3 answers
so just to clarify the answer is 37.313 or 9.3? if i was to round to two decimal places
It should be clear to you that the 37.313 is the number of quarter years, and if I divide that by 4
I would get years
37.313../4 = 9.33 years rounded to 2 decimal places
I would get years
37.313../4 = 9.33 years rounded to 2 decimal places