Asked by Fay
Find the first five terms of the given recursively defined sequence.
an = 3an − 1 + 6 and a1 = 1
a1=
a2=
a3=
a4=
a5=
an = 3an − 1 + 6 and a1 = 1
a1=
a2=
a3=
a4=
a5=
Answers
Answered by
Reiny
I am sure you meant:
a<sub>n</sub> = 3a<sub>(n-1)</sub> + 6
in this notation , given any a<sub>n</sub>
a<sub>n-1 </sub> would be the previous term.
so if a<sub>1</sub> = 1
then a<sub>2</sub> = 3a<sub>1</sub> + 6
= 3(1) + 6 = 9
a<sub>3</sub> = 3a<sub>2</sub> + 6
= 3(9) + 6 = 33
continue building them that way.
a<sub>n</sub> = 3a<sub>(n-1)</sub> + 6
in this notation , given any a<sub>n</sub>
a<sub>n-1 </sub> would be the previous term.
so if a<sub>1</sub> = 1
then a<sub>2</sub> = 3a<sub>1</sub> + 6
= 3(1) + 6 = 9
a<sub>3</sub> = 3a<sub>2</sub> + 6
= 3(9) + 6 = 33
continue building them that way.
Answered by
seby
how did you get 9? on a3?
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