Find the first five terms of the given recursively defined sequence.

Question

an = 3an − 1 + 6 and a1 = 1
a1=
a2=
a3=
a4=
a5=

Answer 1

I am sure you meant:

a_n = 3a_(n-1) + 6

in this notation , given any a_n
a_n-1 would be the previous term.
so if a₁ = 1
then a₂ = 3a₁ + 6
= 3(1) + 6 = 9
a₃ = 3a₂ + 6
= 3(9) + 6 = 33

continue building them that way.

Answer 2

how did you get 9? on a3?