Ask a New Question

Question

Let \displaystyle \int_{5}^{9.5} f(x) dx =4, \ \int_{5}^{6.5} f(x) dx=5, \ \int_{8}^{9.5} f(x)dx =8
10 years ago

Answers

Anonymous
what do you want? The integral from 6.5 to 8? That would be 4-5-8 = -9
10 years ago

Related Questions

Evaluate. int_(pi)^(pi) (sin(x))^(3) (cos(x))^(3) dx int_(1)^(2) 6/t^4 dt int_(-2)^2sqrt(4-x^2)text()dx evaluate the integral Given that \displaystyle \int_0^4 x^3\sqrt{9+x^2} dx = a, what is the value of \lfloor a \rfloor? Given \displaystyle \int_0^{\frac{3\pi}{2}} x^2\cos x \, dx = a - \frac{b\pi^2}{c}, where a, b and c... a. The value of \displaystyle \int_{-2}^{-1} \frac{14}{ 4 x } dx is b. The value of \displaystyle... \int_{4}^{13} f(x) \,dx - \int_{4}^{11} f(x) \,dx = \int_{a}^{b} f(x) \,dx where a= and b= . Let \displaystyle \psi : \mathbb {R} \times (0, \infty ) \displaystyle \to \mathbb {R}^2... COMPUTE \displaystyle \sum _{k=1}^{\infty } \sum _{t=1}^{T} 0.5^ k=\quad compute \displaystyle \sum _{k=1}^{K} \sum _{t=1}^{T} 0.5^ k=\quad
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use