Asked by Muqadas
A 1000 kg car can accelerate from rest to a speed of 25 m/s in 10 s. What average power must the engine of car produce in order to cause this acceleration? Neglect friction losses
Answers
Answered by
Henry
M*g = 1000 * 9.8 = 9800 N. = Wt. of car.
a = 25/10 = 2.5 m/s^2.
d = 0.5a*t^2 = 1.25*10^2 = 125 m.
P = F * d/t = 9800 * 125/10 = 122,500J/s = 122,500 Watts.
a = 25/10 = 2.5 m/s^2.
d = 0.5a*t^2 = 1.25*10^2 = 125 m.
P = F * d/t = 9800 * 125/10 = 122,500J/s = 122,500 Watts.
Answered by
Nazish
First find k.E=1/2mv'2
K.e=1/2 1000x (25)2=
E=312500 j
Now
P=E/t
P=312500/10=31250
Now convert in kilo
31250/1000=31.25 thanks
K.e=1/2 1000x (25)2=
E=312500 j
Now
P=E/t
P=312500/10=31250
Now convert in kilo
31250/1000=31.25 thanks
Answered by
Raj
Answer given by nazish is correct.
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