Question
Solve the exponential by expressing each side as a power of the same base and then equating exponents.
5^x-2/4=squaroots 5
please help. Thanks!
5^x-2/4=squaroots 5
please help. Thanks!
Answers
Reiny
I am going out on a limb here and assume you meant:
5^( (x-2)/4) = √5
5^( (x-2)/4) = 5^(1/2)
(x-2)/4 = 1/2
x-2 = 2
x = 4
The way you typed it ....
5^x - 1/2 = √5
5^x = √5 + 1/2
x log5 = log (√5 + 1/2)
x = log(√5 + 1/2) /log5 = appr .62539
5^( (x-2)/4) = √5
5^( (x-2)/4) = 5^(1/2)
(x-2)/4 = 1/2
x-2 = 2
x = 4
The way you typed it ....
5^x - 1/2 = √5
5^x = √5 + 1/2
x log5 = log (√5 + 1/2)
x = log(√5 + 1/2) /log5 = appr .62539