Question

find the perimeter of the parallelogram with verticles P(-2,2),Q(0,0),R(2,4) and S(0,6) correct to one decimal place

Answer 1

P-Q = sqrt(2^2 + 2^2) = 2 sqrt 2
Q-R = sqrt(4+16) = 2 sqrt 5
R-S = P-Q if a parallelogram = 2 sqrt 2
S-P = Q - R = 2 sqrt 5
so
4 sqrt 2 + 4 sqrt 5
or
4( sqrt 2 + sqrt 5)