Asked by Jean
Paul and Juston are carrying a sack or rice weighing 6.02x10^2 N on a pole between them. If the pole is 2.0 m long and the load is .50m away from Juston,what force should each boy exert to make it equilibrium. Neclect the weight of the pole.
Answers
Answered by
Henry
F1 + F2 = 602 N.
F1 = (1.5/0.5)F2 = 3F2.
3F2 + F2 = 602.
F2 = 150.5 N. = Paul's force.
3F2 = 3 * 150.5 = 451.5 N. = Justin's
force.
F1 = (1.5/0.5)F2 = 3F2.
3F2 + F2 = 602.
F2 = 150.5 N. = Paul's force.
3F2 = 3 * 150.5 = 451.5 N. = Justin's
force.
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