You have to draw the figure to fully understand the problem.
Since CE > CD, Pt E should be near pt B.
Using sine law and cos law. You can get BE = 5.48
You are given triangle ABC. AB=13,BC=15, and CA=14. Point D is on segment BC and CD=6. Point E is on segment BC such that CE>CD and ∠BAE=∠CAD. What is the length of BE?
1 answer