Question

the length of a rectangle is three times of its width. if the length of the diagonal is 8 root 10cm then the area of the parameter of the rectangle ?

Answer 1

area of parameter is gibberish

area = (8√10)(3*8√10)
perimeter = 2(8√10 + 3*8√10)

Answer 2

That's wrong, Steve. You're thinking the length given is the length of the smaller side, but it's actually the length of the diagonal. So one would have to use a^2+b^2=c^2 to find the length of the sides, and from there area can be found. so it'd be
a= the length of the smaller side, or x
b= the length of the larger side, or 3x
and c= the length of the diagonal, or 8√(10)
So just set up the equation and solve for x, then for 3x, and then area.

Answer 3

width --- x
length --- 3x

x^2 + (3x)^2 = (8√10)^2
10x^2 = 640
x^2 = 64
x = 8
width = 8
length = 24
area = (8)(24) = 192

Answer 4

Oops. I misread the diagonal part.
Could not help the gibberish, however.