Question

maths:x^4+3x-2/(x^2+1)^3(x-4)=(Ax+B)/(x^2+1)+(Cx+D)/(x^2+1)^2+(Ex+F)/(x^2+1)^3+G/(x-4)+H/(x-4)^2.fine the value of ABCDEFGH,it a partial fraction o plz i need the solution urgently

Answer 1

This is DEFINITELY NOT "government"!!

Answer 2

(x^4+3x-2)/((x^2+1)^3(x-4))
=

266 / 4913(x-4)
- 266(x+4) / (x^2+1)
+ 23(x+4) / 289(x^2+1)^2
+ (7-11x) / 17(x^2+1)^3

Problems like this are so tedious that they really test only patience, not knowledge.

Answer 3

and there is no (x-4)^2 term, since your original fraction had none. If you really want that to be included, I can only refer you to

http://www.wolframalpha.com/input/?i=%28x^4%2B3x-2%29%2F%28%28x^2%2B1%29^3%28x-4%29^2%29

Scroll down a bit to the partial fraction breakdown.