Asked by sue

Use factoring to solve 5^4-8x^2=0
Not sure where to begin I got
x^2(5x^2)-8=0
Answered by Steve
No, what you got was
x^2(5x^2-8) = 0

so, x=0 or

5x^2-8 = 0
x^2 = 8/5
. . .
Answered by Damon
maybe you mean
5^4 - (8x)^2 = 0 ??????
that would be
25^2 - (8x)^2 =0
(25 - 8x)(25+8x) = 0
8x = 25
or
8x = -25
Answered by Steve
As usual, there are several ways a garbled posting might be interpreted. Damon's way has the advantage of a rational solution. Mine and others, such as

5^4 - (8)x^2

have square roots.
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