Asked by Amy S.
Really need help..I can't figure out how?
A van travelling at 60km/h left Town A for Town B at 7.00am. At 7.30am, a car left Town A for Town B. If the car travelled at an average speed of 80km/h, at what time would it catch up with the van?
A van travelling at 60km/h left Town A for Town B at 7.00am. At 7.30am, a car left Town A for Town B. If the car travelled at an average speed of 80km/h, at what time would it catch up with the van?
Answers
Answered by
Reiny
When the car catches up with the van, they would have both traveled the same distance
let the time from 7:30 am to the catch-up time be t hrs.
distance covered by car = 80t
distance covered by van = 60t + (1/2)(60)
= 60t + 30
80t = 60t + 30
20t = 30
t = 3/2
3/2 hours added to 7:30 am would make it 9:00 am
check:
the car went 80t
= 1.5 hrs at 80 km/h or 120 km
the van went 60t + 30
= (3/2)(60) + 30
= 120
let the time from 7:30 am to the catch-up time be t hrs.
distance covered by car = 80t
distance covered by van = 60t + (1/2)(60)
= 60t + 30
80t = 60t + 30
20t = 30
t = 3/2
3/2 hours added to 7:30 am would make it 9:00 am
check:
the car went 80t
= 1.5 hrs at 80 km/h or 120 km
the van went 60t + 30
= (3/2)(60) + 30
= 120
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