Asked by nakul

Solve (1) TTX=2
(2) 3x+2=5x+7-2x
(3) 6x+2-4x=5+2x-3
Answered by Steve
I assume each equation is separate, so we have

x = 2/π

3x+2 = 5x+7-2x
3x+2 = 3x+7
No solution

6x+2-4x=5+2x-3
2x+2 = 2x+2
infinitely many solutions
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