Question

The only real root of x^3 - 1999x^2+x-1999=0 is 1999. What is the only real root of (x-1)^3-1999(x-1)^2 +(x-1)-1999=0?
A. 1
B. 1998
C. 1999
D. 2000

Answer 1

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Answer 2

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Answer 3

If 1999 is a root of
x^3 - 1999x^2+x-1999=0
then a root of
(x-1)^3-1999(x-1)^2 +(x-1)-1999=0
is a value of x so that
x-1 = 1999

In other words, x=2000