Asked by hila
In a certain right triangle, the lengths of the legs have a sum of 50 and a product of 282. What is the length of the hypothenuse?
A. 44
B. 42
C. 40
D. 25squareroot2
A. 44
B. 42
C. 40
D. 25squareroot2
Answers
Answered by
Steve
If the legs are a and b, and the hypotenuse is c, then
a+b=50
ab=282
c^2 = a^2+b^2 = (a+b)^2 - 2ab
= 2500-564
= 1936
so, c = √1936 = 44
1 2 3 6 47 94 141 282
a+b=50
ab=282
c^2 = a^2+b^2 = (a+b)^2 - 2ab
= 2500-564
= 1936
so, c = √1936 = 44
1 2 3 6 47 94 141 282
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