Question

Jose bautista hits a baseball that travels for 142m before it lands. The flight of the ball can be modelled by a quadratic function in which x is the Horizontal distance the ball has travelled away from jose, and h(x) is the height Vertical distance of the ball at that distance.
1. Assume that the ball was between 0.6m and 1.5m above the ground when it was hit.
a) what would h(142) be?
b) what happens when x=0? What are some possible values for h(x) when x=0
Sorry if someone could even just give me tips on how to do this, I'm so lost.

Answer 1

h(x) = ax^2+bx+c

h(142) = 0, because at that distance the ball hits the ground

h(0) is the initial height when the ball was hit (it has not traveled any distance yet). So, 0.6 <= h(0) <= 1.5

Answer 2

HAHA I need help with that too and i think we are in the same class (*CCH right)
PS. posted if you know the answer

Answer 3

the answer to c) and d)