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A sample of 106 body temperatures resulted in a mean of 98.2 degrees and a standard deviation of .62 degrees. Use these sample statistics to construct a 98% confidence interval estimate of the standard deviation of body temperature of all healthy humans.
10 years ago

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PsyDAG
98% = mean ± Z SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (±.01) and its Z score. Insert data and calculate.
10 years ago

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