Question

In the game of craps, the player rolls two balanced dice, 36 equally likely outcomes, compute the probability the player looses on the first roll if the sum of the dice is 3, 4, or 6.

Answer 1

draw a box or matrix with your 36 possibilities
make an x for win, an o for lose(3,4,6)

0 1 2 3 4 5 6
1 x o o x o x
2 o o x o x x
3 o x o x x x
4 x o x x x x
5 o x the rest x
6
number of o s = 10
so 10/36