Asked by james007
A trapezium ABCD is such that AB//CD and the perpendicular from A to CD is 40cm.if AB=20cm,DA=50cm and CD=60cm.calculate the (i)area of the trapezium (ii)<BCD.pls help me with (ii)
solution so far.(i)area=1/2(20 60)40
=1600cm^2
solution so far.(i)area=1/2(20 60)40
=1600cm^2
Answers
Answered by
Steve
Let P be the base of the perpendicular from A, and Q the base of the perpendicular from B.
APD is a 30-40-50 right triangle.
So, CD=30, making AP=30 and QD=10.
Triangle CQB thus has height 40 and leg CQ=50. So, tan(BCD) = 4/5
APD is a 30-40-50 right triangle.
So, CD=30, making AP=30 and QD=10.
Triangle CQB thus has height 40 and leg CQ=50. So, tan(BCD) = 4/5
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