A picture hangs on the wall suspended by two strings, as shown in the

Question

figure, with θ = 65°. The tension in string 1 is 1.3 N.
(a)Is the tension in string 2 greater than, less than, or equal to the tension in string 1? Explain.
(b) Verify your answer to part (a) by calculating the tension in string 2
(c) What is the weight of the picture?

Answer 1

A baseball player slides into third base with an initial speed of 7.75 m/s. If the coefficient of kinetic friction between the player and the ground is 0.45, how far does the player slide before coming to rest?

Answer 2

1. Are the two strings tied to the same point on the wall?

2. a = u*g = 0.45 * (-9.8)=-4.41 m/s^2.

V^2 = Vo^2 + 2a*d.
V = 0.
Vo = 7.75 m/s.
a = 4.41 m/s^2.
Solve for d.

Answer 3

1a. 1.3*Cos(180-65) = -T2*Cos65.
-0.549 = -0.423T2.
T2 = 1.30 N.

The Tensions are equal because the angles are equal.

Answer 4

Ti*sin(180-65) + T2*sin65 = -Wp*sin270.
1.3*0.90631 + 1.3*90,631 = Wp.
Wp = 2.36 N. = Wt. of picture.