Asked by Patch
If a parallel-plate capacitor in a RC circuit has a 10 C charge on each plate when it is disconnected from the battery, and in 10 sec drops to 10% of its initial charge, what is its capacitance? (Assuming R = 10 ohms)
Not sure which formula to use/
Not sure which formula to use/
Answers
Answered by
Damon
V = Vi e^-(t/RC)
.1 = e^-(10/10C) = e^-(1/C)
ln .1 = -1/C
.1 = e^-(10/10C) = e^-(1/C)
ln .1 = -1/C
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.