A man enters an elevator holding two boxes-one on top of the other. The top has a mass of 6.0 kg and the buttom box has a mass of 8.0 kg. The man sets the two boxes on a metric scale registers a value of 166N; this is the upward force upon the bottom box. Determine the acceleration of the elevator (and boxes) and determine the forces acting between the boxes.
Ps. I need solutin thank you so much....
6 answers
Solution sorry
(Mt+Mb)g+(Mt+Ma)a)=166
solve for a.
now, the aforce between the two boxes:
Mt(g+a) is that force.
solve for a.
now, the aforce between the two boxes:
Mt(g+a) is that force.
thank you so much
acceleration is 11m/s
what is the meaning of Mt,Mb,and Ma?
What is the solution of that?
0 answers