Asked by Charlotte
                A man enters an elevator holding two boxes-one on top of the other. The top has a mass of 6.0 kg and the buttom box has a mass of 8.0 kg. The man sets the two boxes on a metric scale registers a value of 166N; this is the upward force upon the bottom box. Determine the acceleration of the elevator (and boxes) and determine the forces acting between the boxes.
Ps. I need solutin thank you so much....
            
        Ps. I need solutin thank you so much....
Answers
                    Answered by
            Charlotte
            
    Solution sorry
    
                    Answered by
            bobpursley
            
    (Mt+Mb)g+(Mt+Ma)a)=166
solve for a.
now, the aforce between the two boxes:
Mt(g+a) is that force.
    
solve for a.
now, the aforce between the two boxes:
Mt(g+a) is that force.
                    Answered by
            Anonymous
            
    thank you so much
    
                    Answered by
            5rahim sterling#2
            
    acceleration is 11m/s
    
                    Answered by
            Mr Paul
            
    what is the meaning of Mt,Mb,and Ma?
    
                    Answered by
            Alphae Kriztheenzeign
            
    What is the solution of that?
    
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