Asked by Charlotte

A man enters an elevator holding two boxes-one on top of the other. The top has a mass of 6.0 kg and the buttom box has a mass of 8.0 kg. The man sets the two boxes on a metric scale registers a value of 166N; this is the upward force upon the bottom box. Determine the acceleration of the elevator (and boxes) and determine the forces acting between the boxes.

Ps. I need solutin thank you so much....
Answered by Charlotte
Solution sorry
Answered by bobpursley
(Mt+Mb)g+(Mt+Ma)a)=166
solve for a.

now, the aforce between the two boxes:
Mt(g+a) is that force.
Answered by Anonymous
thank you so much
Answered by 5rahim sterling#2
acceleration is 11m/s
Answered by Mr Paul
what is the meaning of Mt,Mb,and Ma?
Answered by Alphae Kriztheenzeign
What is the solution of that?
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