Question
Four identical point charges of q = 4.64 nC are at the four corners of a square with a side length of 13.5 cm as shown in the figure. What charge Q should be placed at the center of the square to keep the other four charges in equilibrum?
Answers
bobpursley
Figure the force on one of the corners (the sum of the forces from the three other corners). Then figure Q such that it balances this force.
Force on one corner:
kQq(1/s^2 *.707 + 1/s^2 (.707)+ 1/*sqrt2*s)^2)
= kqq/s^2*(1.414+.5) check that I did it in my head.
that is the force on each corner.
Now, balance that with Q at distance s*.707
forcebalance=kqQ(1/.5s^2)=2kqQ/s^2
solve for Q. Check my work.
Force on one corner:
kQq(1/s^2 *.707 + 1/s^2 (.707)+ 1/*sqrt2*s)^2)
= kqq/s^2*(1.414+.5) check that I did it in my head.
that is the force on each corner.
Now, balance that with Q at distance s*.707
forcebalance=kqQ(1/.5s^2)=2kqQ/s^2
solve for Q. Check my work.
so would it be
(2)(9.0e9)(4.64)(Q)/0.707^2
(2)(9.0e9)(4.64)(Q)/0.707^2
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