I'll assume you meant
1/(x+1)+1/(x+2)= 2/(x+10)
Putting all over a common denominator, the numerator becomes
(x+2)(x+10) + (x+1)(x+10) = 2(x+1)(x+2)
2x^2+23x+30 = 2x^2+6x+4
I expect you can take it from there, eh? Just beware spurious roots that might make any of the original denominators zero. (Luckily, none in this problem)
Solve : 1/x+1+1/x+2= 2/x+10
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