Question
log (base 3) x^2 = 2log(base 3)4-4log(base 3)5
And I need to solve for x.
And I need to solve for x.
Answers
Steve
assume all logs are base 3. We have
log x^2 = 2log4 - 4log5
log x^2 = log16 - log625
x^2 = 16/625
x = ±4/25
Yes, the -4/25 is a solution, since only x^2 appears, so it's always positive.
log x^2 = 2log4 - 4log5
log x^2 = log16 - log625
x^2 = 16/625
x = ±4/25
Yes, the -4/25 is a solution, since only x^2 appears, so it's always positive.