Asked by Mona
log (base 3) x^2 = 2log(base 3)4-4log(base 3)5
And I need to solve for x.
And I need to solve for x.
Answers
Answered by
Steve
assume all logs are base 3. We have
log x^2 = 2log4 - 4log5
log x^2 = log16 - log625
x^2 = 16/625
x = ±4/25
Yes, the -4/25 is a solution, since only x^2 appears, so it's always positive.
log x^2 = 2log4 - 4log5
log x^2 = log16 - log625
x^2 = 16/625
x = ±4/25
Yes, the -4/25 is a solution, since only x^2 appears, so it's always positive.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.