Asked by Mona

log (base 3) x^2 = 2log(base 3)4-4log(base 3)5

And I need to solve for x.

Answers

Answered by Steve
assume all logs are base 3. We have
log x^2 = 2log4 - 4log5
log x^2 = log16 - log625
x^2 = 16/625
x = ±4/25

Yes, the -4/25 is a solution, since only x^2 appears, so it's always positive.
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