At sea level, the atmospheric pressure is 1.04×10 to the power 5 pa.Assuming g=10ms sq and density of air to be uniform and equal 2 1.3kg m cube find the height of the atmosphere.

Question

Rubab · Accepted Answer

Ok if it is 1.04*10^5 N/m^2 what would be the answere in kN/cm^2

Steve · Answer

of course, the air does not have constant density, but under the given assumptions, you want to convert pressure to meters:

1 pa = 1N/m^2

1.04*10^5 N/m^2 * 1m^3/1.3kg * 1kg/9.8N = 8163m or 8.163km

The folks who have climbed Mt. Everest (7855m) would be interested to know this. They were so close to outer space!

Swapnendu Das · Answer

The answer is 8000m