Asked by alvin
At sea level, the atmospheric pressure is 1.04×10 to the power 5 pa.Assuming g=10ms sq and density of air to be uniform and equal 2 1.3kg m cube find the height of the atmosphere.
Answers
Answered by
Steve
of course, the air does not have constant density, but under the given assumptions, you want to convert pressure to meters:
1 pa = 1N/m^2
1.04*10^5 N/m^2 * 1m^3/1.3kg * 1kg/9.8N = 8163m or 8.163km
The folks who have climbed Mt. Everest (7855m) would be interested to know this. They were so close to outer space!
1 pa = 1N/m^2
1.04*10^5 N/m^2 * 1m^3/1.3kg * 1kg/9.8N = 8163m or 8.163km
The folks who have climbed Mt. Everest (7855m) would be interested to know this. They were so close to outer space!
Answered by
Rubab
Ok if it is 1.04*10^5 N/m^2 what would be the answere in kN/cm^2
Answered by
Swapnendu Das
The answer is 8000m
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