Asked by Lola

A hand exerciser utilizes a coiled spring. A force of 82.0 N is required to compress the string by 0.0191 m. Determine the force needed to compress the spring by 0.0520 m.

Answers

Answered by Damon
F = k x
k = 82/.0191

F = (82/.0191) * .0520
Answered by Lola
thank you! =)
Answered by Damon
You are welcome.
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