Asked by mutale
If y varies directly as square of x and the square root of z and y=3 when x=4 and z=9,find the value of y when x=3 and z=16
Answers
Answered by
Steve
y = k x^2 √z
Or,
y/(x^2 √z) = k and is constant. So,
3/(4^2 √9) = y/(3^2 √16)
Now just solve for y.
Or,
y/(x^2 √z) = k and is constant. So,
3/(4^2 √9) = y/(3^2 √16)
Now just solve for y.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.