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Asked by Anonymous

Problem: Find minimum?maximum for:

y=xa^(1/x)

Ans given: X=ln(a) (min)

Can't get to it.
10 years ago

Answers

Answered by Steve
y = xa^(1/x)
y' = (1/x) a^(1/x) (x - ln(a))

Since the first two terms are never zero, y'=0 when

x = ln(a)


10 years ago
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