Asked by Richa
The pressure of a gas having volume 1800ml. Originally occupying 300ml. at 6 atms. Pressure.
Answers
Answered by
Anonymous
V1=300ml
V2=1800ml
P1=6atm
P2=p
V1×P1=V2×P2
300×6=1800×p
300×6\1800=p
=0atm
P2=0atm
V2=1800ml
P1=6atm
P2=p
V1×P1=V2×P2
300×6=1800×p
300×6\1800=p
=0atm
P2=0atm
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