Asked by fatma
∑ (-1)^((n-1)) . 7/9^(n-1)
n=1 to ∞
n=1 to ∞
Answers
Answered by
Reiny
we have
1 - 7/9 + (7/9)^2 - (7/9)^3 + ...
a = 1 , r = -7/9
sum∞ = a/(1-r)
= 1/(1 - (-7/9) )
= 9/16
1 - 7/9 + (7/9)^2 - (7/9)^3 + ...
a = 1 , r = -7/9
sum∞ = a/(1-r)
= 1/(1 - (-7/9) )
= 9/16
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